binomial cube formula problem 1
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Calculate the following binomial cube formula:
(2x + 3y)³ =
answer:
(2x + 3y)³ =
a³ + 3a²b + 3ab² + b³ =
8x³ + 36x²y + 54xy² + 27y³
how to calculate the parts:
a³ = 2x • 2x • 2x = 8x³
3a²b = 3 • (2x • 2x) • 3y = 36x²y
3ab² = 3 • 2x • (3y • 3y) = 54xy²
b³ = 3y • 3y • 3y = 27y³