rectangle problem 7:
The perimeter of a rectangle is 132 meters and its length is 2 times its width.
calculate a) length and width? b) area?
a) answer length and width
length = 2w
width = w
P = (l + w) * 2
P = (2w + w) * 2
132 = 3w * 2
132 = 6w / : 6
w = 22 meters
l = 2w
l = 2 * 22
l = 44 meters
A: The length of the rectangle is 44 meters and its width is 22 meters.
b) answer area
A = l * w
A = 44 m * 22 m
A = 968 m²
A: The area of the rectangle is 968m².