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rectangle area and perimeter problem 2

rectangle problem 2:


rectangle problem 2

A rectangle has a length of 66 inches and a width of 35 inches

calculate a) area   b) perimeter

more: problems

a) answer area

A = l • w

A = 66 in • 35 in

A = 2 310 in²

A: The area of the rectangle is 2 310 in².

b) answer perimeter

P = (l + w) • 2

P = (66 in + 35 in) • 2

P = 202 in

A: The perimeter of the rectangle is 202 in.